Class 6 chapter 8 – English version math solution is available now in our website. So, you can get it very easily from our popular educational website. Good news for class 6 students! Chapter 8 is discussion about unknown expression of algebra. Many topics of chapter 8 are like as, variable, constant, term, factor of terms and coefficient of algebraic expression.

## Class 6 chapter 8 math solution – English Version

You get here the solution of 1 number to 9 number except 8 number. Here, we discussed about the class 6 chapter 8 math solution – English version . Addition of algebra, Subtraction of algebra, meaning and creative question of chapter 8. If you are a class 6 students this post for you. Below, you get all solution for Class six math. Just following our website, you will get step by step all chapter solution of Class 6 math. If you need chapter 7 math solution just click the link and get your chapter 7 math.

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## 1 number math solution chapter 8 of Class 6

i) X 7 th times.

ii) Addition with 3 times x to 5

iii) 4 times x subtraction from 11th times y

iv) Addition of two times x and three times y multiply by half.

v) Addition of x divided 2 and y divided by 3 subtract from z divided by 5

vi) Addition of 13th time y and 15th times z subtract from 12th times x

vii) Addition of x,y snd z of two third.

## Number 2 solution chapter 8 class six math

i) 5x + 4y

ii) 2a + 3b

iii) 1 dozen= 12, 1 hali = 4

So, 12 pens cost = x tk

1 pen cost = x/12

So, 4 pens cost = x*4/12= x/3 tk Again, 4 bananas cost = y tk So, 1 banana cost = y/4 tk So, 12 bananas cost = y* 12 / 4 = 3y tk

iv) Product of a and b= ab

7th times c = 7c

Ab/ 7c

v) 2x + 5

vi) Robin purchase the total chocolate = 3x + 5

## 3 number solution chapter 8 class 6 math

A) 1 dozen = 12

So, Half dozen = 12/2 = 6

Now,

Cost of 1 exercise book= x tk

So, Cost of 12 exercise book= 12x tk

Again,

Cost of 1 pencil = y tk

So, Cost of 6 pencils = 6y tk

Total cost for 1 dozen exercise book and hald dozon pencil = 12x + 6 y tk

B) Cost of 1 pencil = y tk

Cost of 4 pencil = 4y tk

Again,

1 eraser price = z tk

So, 2 eraser price = 2z tk

Sogib expense total tk=8y + 2z tk

C) 1 exercise book cost = x tk

So, 3 exercise book cost = 3x tk

1 pencil cost = y tk

So,4 pencil cost= 4y tk

Again,

1 eraser cost= z tk

So, Total cost= 3x + 4y+ z tk

She gave the shopkeeper = 100 tk

So, Shopkeeper return tk him= 100 – ( 3x + 4y + z)

## 4 number solution chapter 8

i) ( 2a+ 3b) + (-a – 2b)

= (2a – a) + ( 3b-2b)

= a+b

ii) (4x-5y) + (-2x+ y) + ( 6x + 7y)

= ( 4x -2x+6x) + ( – 5y + y+ 7y)

= 8x + 3y

iii) (7x+ 5y + 2z) + (3x – 6y + 7z) + ( -9x + 4y+z)

= ( 7x+ 3x- 9x)+ ( 5y- 6y + 4y) + ( 2z + 7z + z)

= x + 3y + 10z

iv) ( 5ax – 7ax + 3ax) +( 3by – 11by + 6by)+ ( -14cz- 9cz-8cz)

=ax + ( -by) + ( -31cz)

= ax – by – 31 cz

## 5 number math solution chapter 8

i) ( 12a + 23b) – ( 7a – 2b)

= ( 12a + 23b) + ( -7a + 2b)

= ( 12a -7a) + ( 23b + 2b)

So, the answer is= 5a + 25b

ii) (4x – 5y) – ( 6x + 7y)

Following the math,

= ( 4x – 5y) + ( – 6x – 7y)

2nd line is = (4x – 6x) + ( – 5y – 7y )

= – 2x + ( – 12y)

So, answer is = – 2x – 12y

iii) ( 10x + 5y + 20z) – ( – 9x + 4y + 25z )

= ( 10x + 5y + 20z) + ( 9x – 4y – 25 z)

So, = ( 10x + 9x) + ( 5y – 4y) + (20z – 25z)

= 19x + y + -(5z)

So, answer = 19x + y – 5z

Read more about the another chapter https://newalljobcircular.com/chapter-7-class-6-math-solution/

iv) ( 5px + 8qy – 14rz) – ( – 11qy – 7px + 9crz)

= ( 5px + 8qy – 14rz) + ( 11qy + 7px – 9crz)

= ( 5px + 7px) + ( 8qy + 11qy) + ( 14rz – 9crz)

So, answer is = 12px + 19qy + 14rz – 9crz

v) (20x – 5y +30z) – ( 15z + 4x – 9y)

= ( 20x – 5y + 30z) + ( – 15z – 4x + 9y)

= ( 20x – 4x) + – ( 5y + 9z) + ( 30z – 15z)

So, answer is = 16x + 4y + 15z

## Chapter 8 math 6 Solution

A) According to question,

Length of rectangular board = ( x-3) m And width = 2 m.

So, perimeter of board = 2( length + width)

= 2 ( x-3 + 2) m

= 2 ( x-1) m

So, answer = 2x – 2 m

B) Area of rectangular board=( length * width)

= (x-3) × 2 Square merer

= 2x – 6 Square meter

## 7 number math solution chapter 8

1st column marble is= 2

So, 2nd columns marble = 3

3rd columns marble = 4

4th columns marble = 5

So, 100th columns need marble is = 101

## 9 number math solution chapter 8

Given,

X= 5a + 7b + 9c

Y= b – 3a – 4c

Z= c – 2b + a

Now, x+y+z

=( 5a + 7b + 9c ) + ( b – 3a – 4c) + ( c – 2b + a)

= ( 5a – 3a+a) + ( 7b + b – 2b) + ( 9c – 4c + c)

So, = 3a + 6b +6c

(Here 3 is common)

= 3( a + 2b + 2c)

So, x + y + z = 3 ( a + 2b + 2c) ( showed)