Class 6 chapter 8 math solution – English Version

Class 6 chapter 8 – English version math solution is available now in our website. So, you can get it very easily from our popular educational website. Good news for class 6 students! Chapter 8 is discussion about unknown expression of algebra. Many topics of chapter 8 are like as, variable, constant, term, factor of terms and coefficient of algebraic expression.

Class 6 chapter 8 math solution – English Version

You get here the solution of 1 number to 9 number except 8 number. Here, we discussed about the class 6 chapter 8 math solution – English version . Addition of algebra, Subtraction of algebra, meaning and creative question of chapter 8. If you are a class 6 students this post for you. Below, you get all solution for Class six math. Just following our website, you will get step by step all chapter solution of Class 6 math. If you need chapter 7 math solution just click the link and get your chapter 7 math.

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1 number math solution chapter 8 of Class 6

i) X 7 th times.
ii) Addition with 3 times x to 5
iii) 4 times x subtraction from 11th times y
iv) Addition of two times x and three times y multiply by half.
v) Addition of x divided 2 and y divided by 3 subtract from z divided by 5
vi) Addition of 13th time y and 15th times z subtract from 12th times x
vii) Addition of x,y snd z of two third.

Class 6 chapter 8 math solution - English Version
Class 6 chapter 8 math solution – English Version

Number 2 solution chapter 8 class six math

i) 5x + 4y
ii) 2a + 3b
iii) 1 dozen= 12, 1 hali = 4
So, 12 pens cost = x tk
1 pen cost = x/12
So, 4 pens cost = x4/12= x/3 tk Again, 4 bananas cost = y tk So, 1 banana cost = y/4 tk So, 12 bananas cost = y 12 / 4 = 3y tk
iv) Product of a and b= ab
7th times c = 7c
Ab/ 7c
v) 2x + 5
vi) Robin purchase the total chocolate = 3x + 5

3 number solution chapter 8 class 6 math

A) 1 dozen = 12
So, Half dozen = 12/2 = 6
Now,
Cost of 1 exercise book= x tk
So, Cost of 12 exercise book= 12x tk
Again,
Cost of 1 pencil = y tk
So, Cost of 6 pencils = 6y tk
Total cost for 1 dozen exercise book and hald dozon pencil = 12x + 6 y tk

B) Cost of 1 pencil = y tk
Cost of 4 pencil = 4y tk
Again,
1 eraser price = z tk
So, 2 eraser price = 2z tk
Sogib expense total tk=8y + 2z tk
C) 1 exercise book cost = x tk
So, 3 exercise book cost = 3x tk
1 pencil cost = y tk
So,4 pencil cost= 4y tk
Again,
1 eraser cost= z tk
So, Total cost= 3x + 4y+ z tk
She gave the shopkeeper = 100 tk
So, Shopkeeper return tk him= 100 – ( 3x + 4y + z)

4 number solution chapter 8


i) ( 2a+ 3b) + (-a – 2b)
= (2a – a) + ( 3b-2b)
= a+b
ii) (4x-5y) + (-2x+ y) + ( 6x + 7y)
= ( 4x -2x+6x) + ( – 5y + y+ 7y)
= 8x + 3y
iii) (7x+ 5y + 2z) + (3x – 6y + 7z) + ( -9x + 4y+z)
= ( 7x+ 3x- 9x)+ ( 5y- 6y + 4y) + ( 2z + 7z + z)
= x + 3y + 10z
iv) ( 5ax – 7ax + 3ax) +( 3by – 11by + 6by)+ ( -14cz- 9cz-8cz)
=ax + ( -by) + ( -31cz)
= ax – by – 31 cz

5 number math solution chapter 8


Class 6 chapter 8 math solution - English Version
Class 6 chapter 8 math solution – English Version

i) ( 12a + 23b) – ( 7a – 2b)
= ( 12a + 23b) + ( -7a + 2b)
= ( 12a -7a) + ( 23b + 2b)
So, the answer is= 5a + 25b


ii) (4x – 5y) – ( 6x + 7y)

Following the math,

= ( 4x – 5y) + ( – 6x – 7y)
2nd line is = (4x – 6x) + ( – 5y – 7y )


= – 2x + ( – 12y)
So, answer is = – 2x – 12y


iii) ( 10x + 5y + 20z) – ( – 9x + 4y + 25z )
= ( 10x + 5y + 20z) + ( 9x – 4y – 25 z)
So, = ( 10x + 9x) + ( 5y – 4y) + (20z – 25z)
= 19x + y + -(5z)
So, answer = 19x + y – 5z

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iv) ( 5px + 8qy – 14rz) – ( – 11qy – 7px + 9crz)
= ( 5px + 8qy – 14rz) + ( 11qy + 7px – 9crz)
= ( 5px + 7px) + ( 8qy + 11qy) + ( 14rz – 9crz)
So, answer is = 12px + 19qy + 14rz – 9crz


v) (20x – 5y +30z) – ( 15z + 4x – 9y)
= ( 20x – 5y + 30z) + ( – 15z – 4x + 9y)
= ( 20x – 4x) + – ( 5y + 9z) + ( 30z – 15z)
So, answer is = 16x + 4y + 15z

Chapter 8 math 6 Solution


A) According to question,
Length of rectangular board = ( x-3) m And width = 2 m.
So, perimeter of board = 2( length + width)
= 2 ( x-3 + 2) m
= 2 ( x-1) m
So, answer = 2x – 2 m


B) Area of rectangular board=( length * width)
= (x-3) × 2 Square merer
= 2x – 6 Square meter

7 number math solution chapter 8


1st column marble is= 2
So, 2nd columns marble = 3
3rd columns marble = 4
4th columns marble = 5
So, 100th columns need marble is = 101

9 number math solution chapter 8


Given,
X= 5a + 7b + 9c
Y= b – 3a – 4c
Z= c – 2b + a


Now, x+y+z
=( 5a + 7b + 9c ) + ( b – 3a – 4c) + ( c – 2b + a)
= ( 5a – 3a+a) + ( 7b + b – 2b) + ( 9c – 4c + c)
So, = 3a + 6b +6c

(Here 3 is common)
= 3( a + 2b + 2c)
So, x + y + z = 3 ( a + 2b + 2c) ( showed)

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