Good news for class six students of Bangladesh! Today, we are discuss about the Class 6 Math solution chapter 7 2023- English version . This post is most important for class six students. Chapter 7 discuss about the proper fraction, improper fraction and mixed fraction. Here, you also saw the addition and subtraction of fraction. Multiple and Division of fraction.
When you visit this website you can get the solution of chapter 7 the game of fractions. We will provide you all chapter of math book 2023 step by step. If ypu need chapter 8 solution click the link and get chapter 8.https://newalljobcircular.com/class-6-chapter-8-math-solution-english-version/
1 number math solution chapter 1 class 6
The first step of 4 blank position value is
½×1/5 = 1/10 …. . (i)
3/5×1/2= 3/10….. (ii)
½×1/4= 1/8…….(iii)
6/5×1/2=6/10….(iv)
2nd step of 2 blank value ( left to right)
1/10×3/10= 3/100( value from i and ii)….. (V)
1/8×3/5 = 3/40 ( value from iii and iv)….. ( vi)
Last step value is
3/100×3/40=9/4000
According to condition,
1st step of below 4 blank values is,
½ ÷1/5=1/2×5/1=5/2
3/5÷1/2=3/5×2/1=6/5
1/2 ÷1/4=1/2×4/1=4/2=2
6/5÷1/2=6/5×2/1=12/5
According to conditions,
2nd step two blank value below is( left to right)
5/2÷6/5=5/2×5/6=25/12
2÷12/5=2/1×5/12=10/12=5/6
So, last step value is
25/12÷5/6=25/12×6/5=5/2
So, above and below last value is
9/4000 and 5/2.
Dear students it’s totally your work. But, For your help, you can just following this solution.
2 number math solution chapter 7 class six
A)
According to question,
Three sides length of the garden is 15 meter, 13.5 meter and 12.3 meter.
So, Total length of garden
= ( 15+13.5+12.3) meter
= 40.8 meter
B)
1 meter cost = 75.75 tk
So, 40.8 meter cost = 75.75×40.8 tk
= 3090.6 tk.
How can you calculate the fraction? Follow the fraction chapter of class 6.
3 number question solution chapter 7 class 6
A)
Graph ‘ a’ is a rectangular shape
Here, length = 5.5 cm and width =2.3 cm
So,
Perimeter of rectangular = 2(length + width)
= 2( 5.5+2.3) cm
=15.6 cm
So, Area of rectangular
=(length ×width)
=( 5.5×2.3)
= 12.65 square cm
B) graph B is a Square,
Here, every length is= 3.6 cm
So,
Perimeter of Square
= 4× length
=4×3.6cm
=21.6cm
So, area of Square is
= (length) ^2
=(3.6)^2 Square cm
=12.96 square cm
C)
Graph c is a rambos
Here, every length = 6.8 cm
So, perimeter of rambos
= 4×length
= 4×6.8 cm
=27.2 cm
Here, we see that the rambos is divided by two Triangle.
So, Area of Triangle ACD
=1/2× breadth × height
= ½×(6.8×4.2) Square Cm.
= 14.28 Square Cm.
So, Area=(2×14.28) Square Cm.
= 28.56 square cm.
4 number math solution chapter 7 class 6
Here,
Weight of Man’s Brain is 1/45 part of man’s weight.
If your weight is 45 kg
Then, your brain weight
=45 of 1/45 kg
=45× 1/45 kg
=1 kg
B)
We have 29 bones in our skull and the number of bones in your head are 29/206 of total bones in your body.
If, my bones = x
Then,x of 29/206=29
Or, 29x/206=29
Or, 29x= 29×206
Then,x= 29×206/29
Or, x= 206
C)
Given,
The amount of water in our body is about 2/3 of our body mass.
My weight is= 45 kg
So, water does our body need to remain healthy
= 45 of 2/3 kg
= 45×2/3 kg
So, answer is= 30 kg
5 number math solution chapter 7 class 6
A) The distance between two consecutive saplings is 2/3 metre.
So, 1st plant to 2nd plant distance =2/3 meter
So, 1st plant to 3rd plant distance =2/3+2/3meter=4/3 meter
And, 1st plant to 4th plant distance =3×2/3 meter= 2 meter
So, length of rectangular garden is 2 m.
And, width of rectangular garden is 4/3 m.
Now, Area of garden is= ( 2×4/3)= 8/3 Square meter.
B)
Flower saplings in length = 4
Flower saplings in width= 3
So, total flower saplings =(4×3)=12
6 Number Math solution
Ria’s family has 8 members.
Here, Riya can not take tea.
So, Total members of take tea.=(8-1) = 7
Riya make tea= 0.56 lt.
So, each cup tea will be = ( 0.56÷7)
= 0.08 lt
7 number math solutio
1 kg lentil cost= 105 tk
So, 1.5 kg lentil cost= 105×1.5 tk
Total cost of lentil = 157.5 tk
Again,
1 kg onion cost= 45.50 tk
So, 5 kg onion cost= 45.50×5 tk
And, total cost for onions = 227.5 tk
So, ratul gave the shopkeeper = ( 157.5+227.5) = 385 tk.
8 number math solution
A)
By 1 hr. Shumon can travel 8 km distance
So, by 6 hr Shumon can travel (6×8)km= 48 km.
B)
8 km need for time = 1 hr
So, 30 km need for time = (30÷8)=3.75 hr.
Now, 3.75 hr.
= 3hr + 0.75 hr.
= 3hr + ( 0.75 × 60) minutes.
answer is =3 hr 45 minutes
So, total time need for Sumon 3 hours 45 minutes.
9 number math solution
A)
Total weight of Auhona’s salad in kg
= (1/5+1/4+1/20+1/100+1/125+1/500)kg
=kg (100+125+25+5+4+1/500)
= 260/509 kg
= 26/50 kg
Answer = 13/25 kg
B)
Suppose, Auhona made salad for himself and her Brothers = x
Then, 2 people for make salad = x kg.
So, 1 people for make salad = x/2 kg.
So, 5 people for make salad = x×5/2 kg
From A,
Auhona made salad for 2 people = 23/25
So, need for 5 people = 13/25 +5/2 kg
= 13/10kg
= 1.3kg