Class 7 math solution English Version. Here, you will get the solution of class 7 Maths. Many students of class 7 are searching for math solution in English version. But, they are not get it from any website. We will provide you the absolute solution of class 7 math. This Curriculum are totally new for the class 7 students. That’s why, they are looking for the solution of all chapter math solution. Here, we will provide you step by step of Math solutions. So, you can get chapter by chapter solution of class 7 math. Class 7 math book is totally change this year. So, you have to need this type of article. Moreover, I hope it is very helpful article for class seven students.
Class 7 math solution English version
We have learns about equation and Linear equation, in class 6 and lean to construct equations from real life problems. We shall learn some techniques and applications to solve equations in this chapter of mathematics book for class 7, In class 6, we learns some miles to solve linear equations. Let an are to prove those rules realistically Determine what the unknown values may be from the equilibriums shown below and write down in your exercise book.
Problem 1 we get from the equation
4 Apple = 1 orange + 2 Apple
Or, 4×5 = 1 orange + 2 × 5
Or, 20 = 1 orange + 10
So, 1 orange +10= 20
Or, 1 orange = 20 – 10
Or, 1 orange = 10
Solve of the 2 Number problem
3 guava + 1 banana = 6 guava
Or, 3 guava + 1 banana – 3 guava = 6 guava – 3 guava[Both sides subtract 3 guava]
Or, 1 banana = 3 guava
1 banana = 3×7
Or, 1 banana = 21
We get from the 3 number solution is.
2 cucumbers + 2 strawberry = 4 strawberry + 1 cucumber
Or, 2 cucumbers + 2 strawberry – 1 cucumber = 4 strawberry + 1 cucumber – 1 cucumber
Or, 1 cucumber + 2 strawberry = 4 strawberry
1 cucumber + 2 strawberry – 2 strawberry = 4 strawberry – 2 strawberry
Or, 1 cucumber = 2 strawberry
Or, 2 strawberry = 1 cucumber
2 strawberry = 9[ from the value)
Or, 1 strawberry = 9/2
Or, 1 strawberry = 4.5
From the solution of number 4
2 apple + 1 orange = 7 orange
Or, 2 Apple + 1 orange – 1 orange = 7 orange – 1 orange
Or, 2 Apple = 6 orange
1 Apple = 3 orange
Or, 1 Apple = 3×11
Or, 1 Apple = 33
individual task of Class 7 math solution English version
The rules of balancing scale may also be used to balance the equations. The equilibrium of equations will be preserved if:
Same amount is added on both sides Same amount is subtracted from both sides
1) Both sides are multiplied by same quantity Both sides are divided by same quantity
2) If the equilibrium of an equation remains valid, we shall not change the s solutions of the equation.
Let us try to apply the above decisions to equations. x-4=1 The basic e
Let us try to bring both sides to an equilibrium position, using the balance weights. Gradually put the weights (number of circles) on the balance. Br sides in equilibrium. At the end we shall get x = 5.
Task:
Using a balance and weights, determine the changed equation of the equation x+6= 9 and
Determine the rules of multiplication and division.
a) Add 3 to the equation
b) Subtract 3 from the equation
c) Multiply by 4
d) Divide by 2
A)
X + 6 = 9
Or, x + 6 + 3= 9 + 3
Or, x + 9 = 12
If 3 Added with the equation than the changes of the equation is x + 9 = 12
B) X + 6 = 9
Or, x + 6 – 3 = 9 – 3
Or, x + 3 = 6
So, if 3 subtract from the equation then the changed equation x+3 = 6
C) Multiplied by 4 the algebraic equation is
X + 6 = 9
Or, 4(x+6) = 4×9
Or, 4x + 24 = 36
So, if the equation is multiplied by 4 the changed equation is 4x + 24 = 36
D) Multiplied by 2 the algebraic equation is x+6 = 9
Or, (x+6)÷2 = 9÷2
Or, x/2+6/2 = 9/2
So, x/2 + 3 = 9/2
So, the equation multiplied by 4 then the changes equation is x/2 + 3 = 9/2
Read more : class 6 math solution
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