Linear Equation in One Variable – Class 7 Math Solution – Chapter 12 ( 231 page individual work)

Today, We are discuss about the Linear Equation in One Variable Class 7 Math Solution Chapter 12 ( 231 page individual work). Here, you get Linear Equation in One Variable Class 7 Math Solution Chapter 12 ( 231 page individual work) . Though, it is your individual work but you need for help. So, we are providing the solutions the Class 7 Math Solution of Chapter 12 ( 231page individual work). Moreover, you can read the whole post of class 7 math solution English version.

Linear Equation in One Variable - Class 7 Math Solution - Chapter 12
Linear Equation in One Variable – Class 7 Math Solution – Chapter 12

Linear Equation in One Variable Class 7 Math Solution Chapter 12 ( 231 page individual work)

The height of Tajindong, the highest mountain peak of Bangladesh is 295 meter more than Keokaradong, the second highest mountain peak of Bangladesh. If the height of Tajindong is 1280 metre, then let us find the height of Keokaradong. So, here we will discuss this addition and Linear Equation in One Variable Class 7 Math Solution Chapter 12 ( 231page individual work). What have we learnt? We can call this process as the change of sides of the equation. Now, using balance and weights, determine the changed equations of the following equations. Decide by observing the equations, where you can use exclusion principle of addition, exclusion principle of multiplication, cross multiplication, symmetry law.

Linear Equation in One Variable Class 7 Math Solution Chapter 12 ( 231 page individual work)

2 Number question solution
7x + 5 = 25 from 7x =20
Balance weight, where is the x is balance and +1 is weight. So, Solve the equation is 7x + 5 =25. Now, we investigate the method of 7x + 5 = 25 from 7x = 20
Below the solution of Balance and weight.
7x + 5 = 25
Or, 7x + 5 – 5 = 25 – 5 ( Subtract 5 from both side)
Or, 7x = 20
So, this method following the give up addition system.

Linear Equation in One Variable - Class 7 Math Solution - Chapter 12
Linear Equation in One Variable – Class 7 Math Solution – Chapter 12

3 number math solution


5(3x + 2) = 5 ( 2x + 1) from 3x + 2 = 2x +1
3x + 2 is used for balance and 2x + 1 is weight. So, solve the equilibrium 5(3x + 2) = 5 ( 2x + 1) from 3x + 2 = 2x +1 Now, we investigate the equation 5(3x + 2) = 5 ( 2x + 1) from 3x + 2 = 2x +1
5(3x + 2) = 5 ( 2x + 1)
Or, (3x + 2) = ( 2x + 1) ( divided by 5 in both side)
So, Here give up the multiplication system

Linear Equation in One Variable - Class 7 Math Solution - Chapter 12
Linear Equation in One Variable – Class 7 Math Solution – Chapter 12

4 number math solution

3x/2 = 7/4 from 12x = 14
Now, 3x/2 = 7/4
Or, 4× 3x /2 = 4×7/4
Or, 6x = 7
Now, 6x =7
Or, 2 × 6x = 2 × 7
Or, 12x = 14
Now, we can describe very easily all this equation.
3x/2 = 7/4
Or, 3x × 4 = 7 × 2
Or, 12x = 14
So, this equation used the multiplication system.

5 number math solution
5x + 2 = 7x – 4 from 7x – 4 = 5x + 2
The balanced weight method description is below
5x + 2 = 7x – 4
Or, 7x – 4 = 5x + 2
From this method used the interchange system.

Read more ; Chapter 12 Linear Equation in one variable

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