Today, we are discuss about the class 6 maths chapter 11. This chapter including the unitary method, percentage and ratio. If you want to chapter 11 math solution just read the whole article and get the maths solution.
Class 6 maths chapter 11
Many years ago, The Johann Carl Friedrich Gauss was a brilliant German mathematician and scientist. He has contributed to himself every areas of science and mathematics. Johann Carl Friedrich known by the “Prince of Mathematics” and the “Greatest Mathematician of All Time”. His contributions to mathematics include number of theory, geometry, magnetism, astronomy and optics. He had many thing to influence on every branches of mathematics and science, that’s why, Johann Carl Friedrich one of the most influential mathematicians in this history.
Jadav Chandra Chakravarti was one of the famous mathematicians in Indian subcontinent. The “Emperor of Mathematic”title get from british government. So, He mainly worked on arithmetic. He written the book “Arithmetic” which is very famous. He discusses about many branches of arithmetic . So, he gave the many numerous alternatives to different arithmetical methods.
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CHAPTER 1 : The Story of Numbers
CHAPTER 2 : The Story of Two Dimensional Objects
Now, CHAPTER 3 : Information Investigation and Analysis
CHAPTER 4 : Trees of Prime Factors
CHAPTER 5 : Measurement of Length
Now, CHAPTER 6 : The World of Integers
CHAPTER 7 : The Game of Fractions
CHAPTER 8: World of Unknown expressions
Now, CHAPTER 9: Linear Equation
CHAPTER 10 : Story of Three Dimensional Objects
CHAPTER 11 : Unitary Method, Percentages and Ratio
Now, Chapter 12 : Set the Formula, get the Formula
202 number page math solution
1)
Solution :
Here, the total number of grids is 100 and 49 grids are painted green. So, 49% is colored green. The green-colored shape makes the map of a country, Yes, we have seen it before, it is the map of Bangladesh.
1) What is the percentage of green-colored jarts and red-colored parts, out of the whole part in following picture?
Solution :
A) Green colored part = 50%
Red Colored part = 50%
B) The green-colored shape is like icecream. Yes, I have seen it before. This is an icecream with a stick.
C) Green colored part = 50%
Red Colored part = 50%
D) Green colored part = 46%
Red Colored part = 54%
Unitary Method, Percentages and Ratio
2) What percentage of the gallery is full and what percentage is empty in the following image?
Full part : 22 %
Empty part : 78 %
Find the ratio of the first quantity to the second quantity of the following pairs of numbers:
A) 25 and 335
Solution:
The ratio of 25 and 335
= 25/335
= 5/67; [Dividing numerator and denominator by 5]
So, = 5:67
B)
7×3+1 and 9×5+2
= 22/3 and 47/5
The ratio of 22/3 and 47/5 is
= 110/ 141 ( by the LC.M. of 3 and 5 that is, 15)
C) 1.25 and 7.5
Solution:
The ratio of 1.25 and 7.5 is
= 1.25/7.5
= 125/750
( multiplying by 100)
= 1/6
= 1:6
D) 8×3+2 and 0.125
= 26/3
and 0.125 = 125 / 1000= 1/8
The ratios of 26/3 and 1/8
= 208/3
= 208:3
E) Here,
= 1 year 2 months
=(12+2) months
=14 moths
The ratio of 14 months and 7 months
= 14/7
= 2/1
Now, = 2:1
F)
= 7 kg
So, = (7x 1000) g
= 7000 g
=2 kg 300 g
So, = (2x 1000+300) g
=2300 g
The ratio is =
= 7000/2300
=70/23
=70:23
G) Tk. 2 and 40 paisa
= Tk. 2
=(2x 100) paisa
=200 paisa
The ratio of 200 paisa and 40 paisa
=200/40
=5/1
= 5:1
Class 6 maths – chapter 11
2) Count the number of books and exercise books you brought to class and complete the following tasks:
(a) Find the ratio of the number of exercise books
Solution :
a) I have bought 7 books and 5 Notebooks.
Ratio of number of books and notebooks7:5
(b) Find the ratio of the total number of pages of the exercise books and the books.
(b) The note books are 200 pages each and the books are 120 pages each.
Total number of pages of 7 books 120×7=840 and total number of pages of 5 note books=(200×5)=1000
The ratio of the total number of pages in the books and the total number of pages in the books
= 1000/840 ( Divided by 40)
= 25:21
Class 6 mathematics solutions
3) Find the length and breadth of your Mathematics book using a ruler and find their
ratio.
Solution : The length of the math book= 12 cm and breadth = 8 cm
The ratios of length and breadth = 12/8=3:2
4) Find 3 different tables in your classroom or home or somewhere else.
Solution :
A) Find three different tables. One is the teacher’s table in my classroom, one is the dining table in my home and the other is my reading table. Determine the length and width of the three tables and determine the ratios.
Teacher’s table in the classroom The length of the table is 4 feet and the width is 2 feet
The ratio of length to width = 4/2 = 2/1=2:1
Dining table of the home :
The length of the dining table = 10 and width = 6
So, the ratios of the length and width = 10/6 = 5/3=5:3
My reading table, :
The length of the table is 3 feet and width 2 feet.
The ratios of the table is = 3:2
B) First table ratio = 2:1
Second table ratio is = 5:3
Third table ratio is = 3:2
So, the ratios is highest to lowest = 5:3>3:2>2:1
3)
Solution : The length and width of our flag 10 and 6.
And, the ratios of flag 10:6. This ratio we found when, we read in Bangladesh and General History boo
Class 6 maths chapter 11
6)
Solution :
Given, Height of Shajal
- 1 m 75 cm.
= (1 x 100+75) cm [1m=100 cm.]
=175 cm.
And Height of Shujan
1 m 50 cm
=(1×100+ 50) cm
= ( 100 +50) cm
= 150 cm
The ratio of the height of Shajal and Shujan
175/150
= 7/6
= 7:6
Here, the value of two same type quantities (ie height) with em and m units are given. Taking 1 m = 100 cm. we have converted m to cm.
Textbook page 222 solution
Solve the following problems:
1)
Simplify the following ratios:
(a) 9 : 12
= 9/12
= 3×3/3×4
=3/4
=3:4
(b) 15 : 21
= 3×5/3×7
= 5/7
=5:7
(c)
45 : 36
= 9×5/9×4
= 5/4
=5:4
(D) 65 :26
= 13×5/13×2
= 5/2
Now,, = 5:2
2)
solution
12 : 18
=12/18
=2/3
6 : 18
= 6/18
= 1/3
15 : 10
= 3/2
Unitary Method, Percentages and Ratio
3 : 2
= 3/2
1 : 3
=1/3
2 : 6
= 1/3
12 : 8
= 3/2
3)
Solution
Boys in the School is= 450
Girls in the school is= 500
The ratios of Boys and Girls
= 450/500
= 9/10
So, = 9:10
5)
solution
Given, width : length = 2:5
Width / length = 2/5
Here, length = 50 m
Width / 50= 2/5
Width × 5= 50×2
So, Width = 50×2/5
Width = 20 m
If the length is hall room 50 then, width is 20 m.
Here, width =40
So, 40/length = 2/5
So, length ×2= 40×5
Here, length = 200/2
Length = 100
If width is = 40 then, length of hall room = 200
Here, length 200
Width /200= 2/5
Now, Width ×5= 200×2
Width = 400/5
So, Width = 80
Here, width= 160
160/length = 2/5
Length ×2= 160×5
Length = 800/2
So, Length = 400
If the width of hall room 160 then, length of hall room 400.
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