The article is about the NCTB class 6 math solution chapter 9. Chapter 9 is describe about the Linear Equation. Moreover, This is a mathematical statement and equality. So, Mathematical statement with the sign of equality is called an Equation. Here we say, the unknown quantity x is a variable. Usually, the small letters in the English alphabets like as( a,b,d,x,y,z,p,q) are used for the variable or the unknown quantity and simple equation with unknown quantity or variable is known as a Linear Equation.

## NCTB Class 6 Math solution – Linear Equation

In addition to, The process of finding the unknown quantity or the variable in an equation is called the solution of the equation. So, The value of the solution is the root of the equation. If the value of the root is substituted on both sides of the equation, then the left hand side and right hand side are equal.

## Things to know for finding solutions of equations

- If a quantity is added to each equal quantity of an equation, then the sums

will be equal to each other. - If a quantity is subtracted from each equal quantity, then subtracted results

will be equal to each other - Though, each equal quantity of an equation is multiplied by a quantity, then the

products will be equal. - If each equal quantity is divided by a non-zero quantity, then the quotients

will be equal.

When you are going to solve the problem of Linear Equation then, you have to know about the above rules. Class six students want to solve about the chapter 9 of Linear Equation. I hope, you get here all solution of class 6 math book 2023. Moreover, you see the new curriculum in 2023. So, You have to know about the new curriculum math solution 2023. We are trying to class 6 math solve by easiest method. - READ MORE

## NCTB Class 6 Math solution – Linear Equation

CHAPTER 1 : The Story of Numbers

CHAPTER 2 : The Story of Two Dimensional Objects

CHAPTER 3 : Information Investigation and Analysis

CHAPTER 4 : Trees of Prime Factors

CHAPTER 5 : Measurement of Length

CHAPTER 6 : The World of Integers

CHAPTER 7 : The Game of Fractions part 1

The Game of Fractions : part 2

CHAPTER 8: World of Unknown expressions

CHAPTER 9: Linear Equation

CHAPTER 10 : Story of Three Dimensional Objects

CHAPTER 11 : Unitary Method, Percentages and Ratio

Chapter 12 : Set the Formula, get the Formula

Below, you will see chapter 9 solution.

## 1 number math solution class 6 chapter 9

NCTB Class 6 Math solution – Linear Equationv

Collect your number 1 math from the image.

## 3 number math solution

i) 2x+5= 15

Or, 2x = 15-5

Or, 2x = 10

Or, x= 10/2

Or, x = 5

So, answer is 5

So, x= 10.

Then, lefthand side= 2.10+5=20 + 5 =25,

Whether, is not equal to the right side.

Again, x= -5,

Then, Lefthand side = 2.(-5)+5=-10+5=-5

So, Which is not equal to the right-hand side.

That’s why, 10 and -5 are not base value of 2x+5=15

ii) 5 – y=7

Or, -y=7-5

Or, -y=2

Or, y=2

So main base value = -2

Now,y=12 Then, Lefthand side 5-12 = -7

Which is not equal to right-hand side.

Again, y=2 then,5-2=3

Whether, lefthand side and right-hand side are not equal.

That’s why, 12 and 2 are not the base value of 5-y=7

iii) 5x-2= 3x+8

Or, 5x,-3x=8+2

So,2x= 10

Or, x= 10/5

So, x= 2

So, the main base value =2

## NCTB Class 6 Math solution – Linear Equation

Now, x= 1

Then, Lefthand side

=5.1-2= 3.1 + 8

0r,= 3=11, Which is not equal to the right-hand side.

X= -5 then, Lefthand side = 5, (-5) -2= -25-2= -27

Right-hand side =3.-5) + 8 = -7

Whether, two side are not equal

That’s why 1 and -5 are base value of 5x-2= 3x+8

iv) 2y+2= 16

Or, 2y= 16-2

Or, 2y=14

Or, y= 14/2

So,y = 7

So, main base value = 7

Now, y= 18 Then,

Lefthand side, 2.18 + 2 =36+2=38

So, which is not equal to the right-hand side.

Again, x= 9 Then, left hand side= 2. 9 + 2 =18 + 2 =20

So, which is not equal to the right side.

That’s why, 18 and 9 are not base value of 2y+2= 16

v) 4z – 5 = 2z + 19

Or, 4z – 2z = 19+5

Or, 2z = 24

Or, z= 24/2

Or, z = 12

So, right base value= 12

Now, z=7 Then, Lefthand side = 4.7 -5=28-5=23

Right-hand side = 2.7 + 19 =14+19=33

So, two part are not equal

Again, z=4

Then, lefthand side = 4.4-5= 16-5=11

Right-hand side = 2.4+19=8+19=27

So, two sides are not equal.

That’s why, 7 and 4 are not base value of 4z-5=2z+19

## 4 number math solution chapter 9

a)

1 dozen = 12

1 pen price = x tk

12 pen price =12x tk

So, 100-12x=40

Or, -12x= 40-100

Or,-12x= -60

Or, 12 x= 60

Or, x= 60/12

Or, x= 5

So, Every pen price =5 tk

b) 1 exercise book price= 12 tk

Y exercise book price =12y tk

So,

40-12y=4

Or, -12y= 4-40

Or, -12y = -36

Or, 12y =36

Or, y= 36/12

Or,y=3

So, mina purchase exercise book=3

## 5 number NCTB math solution class 6 chapter 9

Suppose, Mr Karim invest x tk by 10% profit

So, Mr Karim invest tk (56000 – x) by 12% profit.

Given that,

(56000-x) ×12%+x×10%=6400

Or, (56000-x) ×12/100+x×10/100 =6400

Or, (56000-x) ×12+x×10= 6400 ×100 ( multiplying by 100 both side)

Or, 56000 × 12 -12x +10x= 640000

Or, -2x = 640000 – 672000

Or, -2x = -32000

Or, 2x= 32000

Or, x= 32000/2

So, x= 16000

So, Mr Karim invest 16000. Tk by 10% profit

## 6 number math solution class 6 chapter 9

We know that, A Cricket match century means 100 runs and double century means 200 runs.

So, The total runs of Sakib and Mushfiqur = (200-2)= 198 runs

Suppose, Runs of Mushfiqur = x

So, run of sakib = 2x

According to question,

X+2x= 198

Or, 3x = 198

Or, x= 198/3

Or, x= 66

So, Run of Musfiqur = 66 and Run of Shakib run= 66×2 = 132 run

## 8 number math solution class6 chapter 9

8) a.

So, The number of water bottle = x

1 water bottle weight = 150 gm

Weight of bag = 50 gm

Weight of water bottle + weight of bag= y

So,

1 water bottle weight is = 150gm

So, x water bottle weight = 150x gm

We know that,

Bottle weight + Bag weight = y

So, 150x + 50= y

So, the equation is = 150x + 50= y

B) From’ a ‘ we get,

150x + 50 = y

Or, y= 150x + 50

Or, y= 150×15 + 50

So, y= 2300

C) we get from ‘a’,

150x + 50 = y

Or, 150x + 50 = 1100

Or, 150x = 1100 – 50

Or, 150x = 1050

Or, x= 1050/150

So, x= 7

9 number math solution class 6 chapter 9

9) a.

1 packet biscuit price = 20 tk

So, X packet biscuit price = 20x tk

Now, x packet biscuit price + 1 bottle drink price = y tk

Or, 20x + 15 = y

So, The relations of x and y= 20x + 15 = y

B,

Or, 20×25 +15= y

Or, 500 + 15 = y

So, y, = 515

C.

So, From ‘a’ we get,

20x + 15 = y

Or, 20x + 15 = 255

Or, 20x = 255 – 15

Or, 20x = 240

Or, x= 240/20

So, x= 12

## 10 number math solution class 6 chapter 9

- A) Given that,

Width of field = x merer

Length of field = x + 16 meter

So, Perimeter of the field

= 2×( length + width)

= 2 × ( x + 16 + x) meter

= 2 × ( 2x + 16) meter

= 4x + 32 meter

So, The perimeter is = 4x + 32 meter - So, Below the number B

B)

Given that, perimeter of field = 120 meter

Now, from a we get, The perimeter is = 4x + 32

So, 4x + 32 = 120

Or, 4x = 120 – 32

Or, 4x = 88

Or, x = 88/4

So, x = 22

Width of field = 22 meter

So, length of field = 22 + 16 meter.

So, length = 38 meter

So, Area of field

= (length × width) Square

= ( 38 × 22) Square Meter

So, answer is = 836 Square meter

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